3/3x+4/x=5

Solution for 3/3x+4/x=5 equation:

3/3x+4/x=5

We move all terms to the left:

3/3x+4/x-(5)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: x!=0

x∈R


We calculate fractions


3x/3x^2+12x/3x^2-5=0

We multiply all the terms by the denominator


3x+12x-5*3x^2=0

We add all the numbers together, and all the variables

15x-5*3x^2=0

Wy multiply elements

-15x^2+15x=0

a = -15; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·(-15)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*-15}=\frac{-30}{-30}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*-15}=\frac{0}{-30}
=0
$