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3/2y+y=55
We move all terms to the left:
3/2y+y-(55)=0
Domain of the equation: 2y!=0We add all the numbers together, and all the variables
y!=0/2
y!=0
y∈R
y+3/2y-55=0
We multiply all the terms by the denominator
y*2y-55*2y+3=0
Wy multiply elements
2y^2-110y+3=0
a = 2; b = -110; c = +3;
Δ = b2-4ac
Δ = -1102-4·2·3
Δ = 12076
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12076}=\sqrt{4*3019}=\sqrt{4}*\sqrt{3019}=2\sqrt{3019}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-110)-2\sqrt{3019}}{2*2}=\frac{110-2\sqrt{3019}}{4} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-110)+2\sqrt{3019}}{2*2}=\frac{110+2\sqrt{3019}}{4} $
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