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3/2x-x=x-12
We move all terms to the left:
3/2x-x-(x-12)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
-1x+3/2x-(x-12)=0
We get rid of parentheses
-1x+3/2x-x+12=0
We multiply all the terms by the denominator
-1x*2x-x*2x+12*2x+3=0
Wy multiply elements
-2x^2-2x^2+24x+3=0
We add all the numbers together, and all the variables
-4x^2+24x+3=0
a = -4; b = 24; c = +3;
Δ = b2-4ac
Δ = 242-4·(-4)·3
Δ = 624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{624}=\sqrt{16*39}=\sqrt{16}*\sqrt{39}=4\sqrt{39}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{39}}{2*-4}=\frac{-24-4\sqrt{39}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{39}}{2*-4}=\frac{-24+4\sqrt{39}}{-8} $
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