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3/2x-8=4x
We move all terms to the left:
3/2x-8-(4x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
-4x+3/2x-8=0
We multiply all the terms by the denominator
-4x*2x-8*2x+3=0
Wy multiply elements
-8x^2-16x+3=0
a = -8; b = -16; c = +3;
Δ = b2-4ac
Δ = -162-4·(-8)·3
Δ = 352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{352}=\sqrt{16*22}=\sqrt{16}*\sqrt{22}=4\sqrt{22}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4\sqrt{22}}{2*-8}=\frac{16-4\sqrt{22}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4\sqrt{22}}{2*-8}=\frac{16+4\sqrt{22}}{-16} $
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