3/2x-7=-5/3x+12

Solution for 3/2x-7=-5/3x+12 equation:

3/2x-7=-5/3x+12

We move all terms to the left:

3/2x-7-(-5/3x+12)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 3x+12)!=0

x∈R


We get rid of parentheses

3/2x+5/3x-12-7=0

We calculate fractions


9x/6x^2+10x/6x^2-12-7=0

We add all the numbers together, and all the variables

9x/6x^2+10x/6x^2-19=0

We multiply all the terms by the denominator


9x+10x-19*6x^2=0

We add all the numbers together, and all the variables

19x-19*6x^2=0

Wy multiply elements

-114x^2+19x=0

a = -114; b = 19; c = 0;
Δ = b2-4ac
Δ = 192-4·(-114)·0
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-19}{2*-114}=\frac{-38}{-228}
=1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+19}{2*-114}=\frac{0}{-228}
=0
$