3/2x-4=3-9/x

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Solution for 3/2x-4=3-9/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(3/2)*x-4 = 3-(9/x) // - 3-(9/x)

(3/2)*x+9/x-4-3 = 0

3/2*x^1+9*x^-1-7*x^0 = 0

(3/2*x^2-7*x^1+9*x^0)/(x^1) = 0 // * x^2

x^1*(3/2*x^2-7*x^1+9*x^0) = 0

x^1

(3/2)*x^2-7*x+9 = 0

(3/2)*x^2-7*x+9 = 0

DELTA = (-7)^2-(4*9*(3/2))

DELTA = -5

DELTA < 0

x in { } 

x belongs to the empty set

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