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3/2x+5=x-14
We move all terms to the left:
3/2x+5-(x-14)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
3/2x-x+14+5=0
We multiply all the terms by the denominator
-x*2x+14*2x+5*2x+3=0
Wy multiply elements
-2x^2+28x+10x+3=0
We add all the numbers together, and all the variables
-2x^2+38x+3=0
a = -2; b = 38; c = +3;
Δ = b2-4ac
Δ = 382-4·(-2)·3
Δ = 1468
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1468}=\sqrt{4*367}=\sqrt{4}*\sqrt{367}=2\sqrt{367}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-2\sqrt{367}}{2*-2}=\frac{-38-2\sqrt{367}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+2\sqrt{367}}{2*-2}=\frac{-38+2\sqrt{367}}{-4} $
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