3/2x+3=6/4x+5

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Solution for 3/2x+3=6/4x+5 equation: 



3/2x+3=6/4x+5

We move all terms to the left:

3/2x+3-(6/4x+5)=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R





Domain of the equation: 4x+5)!=0

x∈R



We get rid of parentheses

3/2x-6/4x-5+3=0

We calculate fractions


12x/8x^2+(-12x)/8x^2-5+3=0

We add all the numbers together, and all the variables

12x/8x^2+(-12x)/8x^2-2=0

We multiply all the terms by the denominator


12x+(-12x)-2*8x^2=0

Wy multiply elements

-16x^2+12x+(-12x)=0

We get rid of parentheses

-16x^2+12x-12x=0

We add all the numbers together, and all the variables

-16x^2=0

a = -16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-16)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-32}=0$

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