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3/2x+2x+5/2x=91
We move all terms to the left:
3/2x+2x+5/2x-(91)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
2x+3/2x+5/2x-91=0
We multiply all the terms by the denominator
2x*2x-91*2x+3+5=0
We add all the numbers together, and all the variables
2x*2x-91*2x+8=0
Wy multiply elements
4x^2-182x+8=0
a = 4; b = -182; c = +8;
Δ = b2-4ac
Δ = -1822-4·4·8
Δ = 32996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{32996}=\sqrt{4*8249}=\sqrt{4}*\sqrt{8249}=2\sqrt{8249}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-182)-2\sqrt{8249}}{2*4}=\frac{182-2\sqrt{8249}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-182)+2\sqrt{8249}}{2*4}=\frac{182+2\sqrt{8249}}{8} $
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