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3/2x+2/5x=25
We move all terms to the left:
3/2x+2/5x-(25)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 5x!=0We calculate fractions
x!=0/5
x!=0
x∈R
15x/10x^2+4x/10x^2-25=0
We multiply all the terms by the denominator
15x+4x-25*10x^2=0
We add all the numbers together, and all the variables
19x-25*10x^2=0
Wy multiply elements
-250x^2+19x=0
a = -250; b = 19; c = 0;
Δ = b2-4ac
Δ = 192-4·(-250)·0
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-19}{2*-250}=\frac{-38}{-500} =19/250 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+19}{2*-250}=\frac{0}{-500} =0 $
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