3/2x+1=3/4x+4

Solution for 3/2x+1=3/4x+4 equation:

3/2x+1=3/4x+4

We move all terms to the left:

3/2x+1-(3/4x+4)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 4x+4)!=0

x∈R


We get rid of parentheses

3/2x-3/4x-4+1=0

We calculate fractions


12x/8x^2+(-6x)/8x^2-4+1=0

We add all the numbers together, and all the variables

12x/8x^2+(-6x)/8x^2-3=0

We multiply all the terms by the denominator


12x+(-6x)-3*8x^2=0

Wy multiply elements

-24x^2+12x+(-6x)=0

We get rid of parentheses

-24x^2+12x-6x=0

We add all the numbers together, and all the variables

-24x^2+6x=0

a = -24; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-24)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-24}=\frac{-12}{-48}
=1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-24}=\frac{0}{-48}
=0
$