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3/2x+11/4x=34
We move all terms to the left:
3/2x+11/4x-(34)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 4x!=0We calculate fractions
x!=0/4
x!=0
x∈R
12x/8x^2+22x/8x^2-34=0
We multiply all the terms by the denominator
12x+22x-34*8x^2=0
We add all the numbers together, and all the variables
34x-34*8x^2=0
Wy multiply elements
-272x^2+34x=0
a = -272; b = 34; c = 0;
Δ = b2-4ac
Δ = 342-4·(-272)·0
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-34}{2*-272}=\frac{-68}{-544} =1/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+34}{2*-272}=\frac{0}{-544} =0 $
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