3/2x+1+9/34x=9000

Solution for 3/2x+1+9/34x=9000 equation:

3/2x+1+9/34x=9000

We move all terms to the left:

3/2x+1+9/34x-(9000)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 34x!=0

x!=0/34

x!=0

x∈R


We add all the numbers together, and all the variables

3/2x+9/34x-8999=0

We calculate fractions


102x/68x^2+18x/68x^2-8999=0

We multiply all the terms by the denominator


102x+18x-8999*68x^2=0

We add all the numbers together, and all the variables

120x-8999*68x^2=0

Wy multiply elements

-611932x^2+120x=0

a = -611932; b = 120; c = 0;
Δ = b2-4ac
Δ = 1202-4·(-611932)·0
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-120}{2*-611932}=\frac{-240}{-1223864}
=30/152983
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+120}{2*-611932}=\frac{0}{-1223864}
=0
$