3/2u+4=(3-9)/u

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Solution for 3/2u+4=(3-9)/u equation: 


D( u )

u = 0

u = 0

u = 0

u in (-oo:0) U (0:+oo)

(3/2)*u+4 = (3-9)/u // - (3-9)/u

(3/2)*u-((3-9)/u)+4 = 0

3/2*u^1+6*u^-1+4*u^0 = 0

(3/2*u^2+4*u^1+6*u^0)/(u^1) = 0 // * u^2

u^1*(3/2*u^2+4*u^1+6*u^0) = 0

u^1

(3/2)*u^2+4*u+6 = 0

(3/2)*u^2+4*u+6 = 0

DELTA = 4^2-(4*6*(3/2))

DELTA = -20

DELTA < 0

u in { } 

u belongs to the empty set

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