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3/2p=2/3p+5
We move all terms to the left:
3/2p-(2/3p+5)=0
Domain of the equation: 2p!=0
p!=0/2
p!=0
p∈R
Domain of the equation: 3p+5)!=0We get rid of parentheses
p∈R
3/2p-2/3p-5=0
We calculate fractions
9p/6p^2+(-4p)/6p^2-5=0
We multiply all the terms by the denominator
9p+(-4p)-5*6p^2=0
Wy multiply elements
-30p^2+9p+(-4p)=0
We get rid of parentheses
-30p^2+9p-4p=0
We add all the numbers together, and all the variables
-30p^2+5p=0
a = -30; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-30)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-30}=\frac{-10}{-60} =1/6 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-30}=\frac{0}{-60} =0 $
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