3/2p-p=27

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Solution for 3/2p-p=27 equation:



3/2p-p=27
We move all terms to the left:
3/2p-p-(27)=0
Domain of the equation: 2p!=0
p!=0/2
p!=0
p∈R
We add all the numbers together, and all the variables
-1p+3/2p-27=0
We multiply all the terms by the denominator
-1p*2p-27*2p+3=0
Wy multiply elements
-2p^2-54p+3=0
a = -2; b = -54; c = +3;
Δ = b2-4ac
Δ = -542-4·(-2)·3
Δ = 2940
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{2940}=\sqrt{196*15}=\sqrt{196}*\sqrt{15}=14\sqrt{15}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-14\sqrt{15}}{2*-2}=\frac{54-14\sqrt{15}}{-4} $
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+14\sqrt{15}}{2*-2}=\frac{54+14\sqrt{15}}{-4} $

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