3/2n+5/3n=-133/36

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Solution for 3/2n+5/3n=-133/36 equation:



3/2n+5/3n=-133/36
We move all terms to the left:
3/2n+5/3n-(-133/36)=0
Domain of the equation: 2n!=0
n!=0/2
n!=0
n∈R
Domain of the equation: 3n!=0
n!=0/3
n!=0
n∈R
We get rid of parentheses
3/2n+5/3n+133/36=0
We calculate fractions
2394n^2/648n^2+972n/648n^2+1080n/648n^2=0
We multiply all the terms by the denominator
2394n^2+972n+1080n=0
We add all the numbers together, and all the variables
2394n^2+2052n=0
a = 2394; b = 2052; c = 0;
Δ = b2-4ac
Δ = 20522-4·2394·0
Δ = 4210704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4210704}=2052$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2052)-2052}{2*2394}=\frac{-4104}{4788} =-6/7 $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2052)+2052}{2*2394}=\frac{0}{4788} =0 $

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