3/2h-10=4h

Solution for 3/2h-10=4h equation:

3/2h-10=4h

We move all terms to the left:

3/2h-10-(4h)=0


Domain of the equation: 2h!=0

h!=0/2

h!=0

h∈R


We add all the numbers together, and all the variables

-4h+3/2h-10=0

We multiply all the terms by the denominator


-4h*2h-10*2h+3=0

Wy multiply elements

-8h^2-20h+3=0

a = -8; b = -20; c = +3;
Δ = b2-4ac
Δ = -202-4·(-8)·3
Δ = 496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{496}=\sqrt{16*31}=\sqrt{16}*\sqrt{31}=4\sqrt{31}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-4\sqrt{31}}{2*-8}=\frac{20-4\sqrt{31}}{-16}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+4\sqrt{31}}{2*-8}=\frac{20+4\sqrt{31}}{-16}
$