3/2b+7=b

Solution for 3/2b+7=b equation:

3/2b+7=b

We move all terms to the left:

3/2b+7-(b)=0


Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R


We add all the numbers together, and all the variables

-1b+3/2b+7=0

We multiply all the terms by the denominator


-1b*2b+7*2b+3=0

Wy multiply elements

-2b^2+14b+3=0

a = -2; b = 14; c = +3;
Δ = b2-4ac
Δ = 142-4·(-2)·3
Δ = 220
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{220}=\sqrt{4*55}=\sqrt{4}*\sqrt{55}=2\sqrt{55}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{55}}{2*-2}=\frac{-14-2\sqrt{55}}{-4}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{55}}{2*-2}=\frac{-14+2\sqrt{55}}{-4}
$