3/2(x-8)=1/3(2x+4)

Solution for 3/2(x-8)=1/3(2x+4) equation:

3/2(x-8)=1/3(2x+4)

We move all terms to the left:

3/2(x-8)-(1/3(2x+4))=0


Domain of the equation: 2(x-8)!=0

x∈R



Domain of the equation: 3(2x+4))!=0

x∈R


We calculate fractions


(9x2/(2(x-8)*3(2x+4)))+(-2xx/(2(x-8)*3(2x+4)))=0


We calculate terms in parentheses: +(9x2/(2(x-8)*3(2x+4))), so:

9x2/(2(x-8)*3(2x+4))

We multiply all the terms by the denominator


9x2

We add all the numbers together, and all the variables

9x^2

Back to the equation:

+(9x^2)



We calculate terms in parentheses: +(-2xx/(2(x-8)*3(2x+4))), so:

-2xx/(2(x-8)*3(2x+4))

We multiply all the terms by the denominator


-2xx

Back to the equation:

+(-2xx)


We get rid of parentheses

9x^2-2xx=0