3/2(x-1)=1/6(x+3)

Solution for 3/2(x-1)=1/6(x+3) equation:

3/2(x-1)=1/6(x+3)

We move all terms to the left:

3/2(x-1)-(1/6(x+3))=0


Domain of the equation: 2(x-1)!=0

x∈R



Domain of the equation: 6(x+3))!=0

x∈R


We calculate fractions


(18xx/(2(x-1)*6(x+3)))+(-2xx/(2(x-1)*6(x+3)))=0


We calculate terms in parentheses: +(18xx/(2(x-1)*6(x+3))), so:

18xx/(2(x-1)*6(x+3))

We multiply all the terms by the denominator


18xx

Back to the equation:

+(18xx)



We calculate terms in parentheses: +(-2xx/(2(x-1)*6(x+3))), so:

-2xx/(2(x-1)*6(x+3))

We multiply all the terms by the denominator


-2xx

Back to the equation:

+(-2xx)


We get rid of parentheses

18xx-2xx=0