3/2(x+4)+2x-3=10

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Solution for 3/2(x+4)+2x-3=10 equation: 


x in (-oo:+oo)

(3/2)*(x+4)+2*x-3 = 10 // - 10

(3/2)*(x+4)+2*x-10-3 = 0

3/2*(x+4)+2*x-10-3 = 0

3/2*(x+4)+2*x-10-3 = 0

7/2*x-10-3+6 = 0

7/2*x-4-3 = 0

7/2*x-7 = 0

7/2*x-7 = 0

7/2*x-7 = 0 // + 7

7/2*x = 7 // : 7/2

x = 7/7/2

x = 2

x = 2

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