3/2(x+4)+2R-3=10

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Solution for 3/2(x+4)+2R-3=10 equation: 



3/2(x+4)+2-3=10

We move all terms to the left:

3/2(x+4)+2-3-(10)=0



Domain of the equation: 2(x+4)!=0

x∈R



We add all the numbers together, and all the variables

3/2(x+4)-11=0

We multiply all the terms by the denominator


-11*2(x+4)+3=0

Wy multiply elements

-22x(x+3=0

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