3/2(n+12)=1/2(2n-6)

Solution for 3/2(n+12)=1/2(2n-6) equation:

3/2(n+12)=1/2(2n-6)

We move all terms to the left:

3/2(n+12)-(1/2(2n-6))=0


Domain of the equation: 2(n+12)!=0

n∈R



Domain of the equation: 2(2n-6))!=0

n∈R


We calculate fractions


(6n2/(2(n+12)*2(2n-6)))+(-2nn/(2(n+12)*2(2n-6)))=0


We calculate terms in parentheses: +(6n2/(2(n+12)*2(2n-6))), so:

6n2/(2(n+12)*2(2n-6))

We multiply all the terms by the denominator


6n2

We add all the numbers together, and all the variables

6n^2

Back to the equation:

+(6n^2)



We calculate terms in parentheses: +(-2nn/(2(n+12)*2(2n-6))), so:

-2nn/(2(n+12)*2(2n-6))

We multiply all the terms by the denominator


-2nn

Back to the equation:

+(-2nn)


We get rid of parentheses

6n^2-2nn=0