3/2(b-20)=7/5(5b-3)

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Solution for 3/2(b-20)=7/5(5b-3) equation: 


b in (-oo:+oo)

(3/2)*(b-20) = (7/5)*(5*b-3) // - (7/5)*(5*b-3)

(3/2)*(b-20)-((7/5)*(5*b-3)) = 0

(3/2)*(b-20)+(-7/5)*(5*b-3) = 0

3/2*(b-20)-7/5*(5*b-3) = 0

3/2*(b-20)-7/5*(5*b-3) = 0

-11/2*b-129/5 = 0

-11/2*b-129/5 = 0

-11/2*b-129/5 = 0 // + 129/5

-11/2*b = 129/5 // : -11/2

b = 129/5/(-11/2)

b = -258/55

b = -258/55

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