3/2(8x-4)-4(2x-3)=-10

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Solution for 3/2(8x-4)-4(2x-3)=-10 equation: 



3/2(8x-4)-4(2x-3)=-10

We move all terms to the left:

3/2(8x-4)-4(2x-3)-(-10)=0



Domain of the equation: 2(8x-4)!=0

x∈R



We add all the numbers together, and all the variables

3/2(8x-4)-4(2x-3)+10=0

We multiply parentheses

3/2(8x-4)-8x+12+10=0

We multiply all the terms by the denominator


-8x*2(8x-4)+12*2(8x-4)+10*2(8x-4)+3=0

Wy multiply elements

-16x^2(8+24x(8+20x(8+3=0

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