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3/2(4x-2)-3x=5-(x+2)
We move all terms to the left:
3/2(4x-2)-3x-(5-(x+2))=0
Domain of the equation: 2(4x-2)!=0We add all the numbers together, and all the variables
x∈R
-3x+3/2(4x-2)-(5-(x+2))=0
We multiply all the terms by the denominator
-3x*2(4x-2)-((5-(x+2)))*2(4x-2)+3=0
We calculate terms in parentheses: -((5-(x+2)))*2(4x-2), so:Wy multiply elements
(5-(x+2)))*2(4x-2
-6x^2(4-((5-(x+2)))*2(4x-2)+3=0
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