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3/2(4x-1)-3=5/4-(x+2)
We move all terms to the left:
3/2(4x-1)-3-(5/4-(x+2))=0
Domain of the equation: 2(4x-1)!=0
x∈R
Domain of the equation: 4-(x+2))!=0We calculate fractions
We move all terms containing x to the left, all other terms to the right
-(x+2))!=-4
x∈R
(-(x+2))+3*4)/(32x-(x+2))-8)+(-10x4/(32x-(x+2))-8)-3=0
We calculate terms in parentheses: +(-(x+2)), so:We get rid of parentheses
-(x+2)
We get rid of parentheses
-x-2
We add all the numbers together, and all the variables
-1x-2
Back to the equation:
+(-1x-2)
-1x+3*4)/(32x-(x+2))-8)+(-10x4/(32x-(x+2))-8)-3-2=0
We multiply all the terms by the denominator
-1x*(32x+3*4)-(x+2))-8)+(-10x4-((x+2))-8)-3-2)*(32x=0
We add all the numbers together, and all the variables
-1x*(32x+12)-(x+2))-8)+(-10x4-((x+2))-8)-3-2)*(32x=0
We multiply parentheses
-32x^2-12x-(x+2))-8)+(-10x4-((x+2))-8)-3-2)*(32x=0
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