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3/2(4x+1)+3x=5/4-(x+2)
We move all terms to the left:
3/2(4x+1)+3x-(5/4-(x+2))=0
Domain of the equation: 2(4x+1)!=0
x∈R
Domain of the equation: 4-(x+2))!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-(x+2))!=-4
x∈R
3x+3/2(4x+1)-(5/4-(x+2))=0
We calculate fractions
3x+(-(x+2))+3*4)/(32x-(x+2))+8)+(-10x4/(32x-(x+2))+8)=0
We calculate terms in parentheses: +(-(x+2)), so:We get rid of parentheses
-(x+2)
We get rid of parentheses
-x-2
We add all the numbers together, and all the variables
-1x-2
Back to the equation:
+(-1x-2)
3x-1x+3*4)/(32x-(x+2))+8)+(-10x4/(32x-x-2-2))+8=0
We multiply all the terms by the denominator
3x*(32x-1x*(32x+3*4)-(x+2))-10x4-x*(32x-2*(32x-2)+8)*(32x+8)+(=0
We add all the numbers together, and all the variables
3x*(32x-1x*(32x+12)-(x+2))-10x4-x*(32x-2*(32x-2)+8)*(32x+8)+(=0
We add all the numbers together, and all the variables
-10x^4+3x*(32x-1x*(32x+12)-(x+2))-x*(32x-2*(32x-2)+8)*(32x+8)=0
We do not support expression: x^4
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