3/2(2x+3)=3/2(x+6)

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Solution for 3/2(2x+3)=3/2(x+6) equation: 



3/2(2x+3)=3/2(x+6)

We move all terms to the left:

3/2(2x+3)-(3/2(x+6))=0



Domain of the equation: 2(2x+3)!=0

x∈R





Domain of the equation: 2(x+6))!=0

x∈R



We calculate fractions


(6xx/(2(2x+3)*2(x+6)))+(-6x2/(2(2x+3)*2(x+6)))=0



We calculate terms in parentheses: +(6xx/(2(2x+3)*2(x+6))), so:

6xx/(2(2x+3)*2(x+6))

We multiply all the terms by the denominator


6xx

Back to the equation:

+(6xx)





We calculate terms in parentheses: +(-6x2/(2(2x+3)*2(x+6))), so:

-6x2/(2(2x+3)*2(x+6))

We multiply all the terms by the denominator


-6x2

We add all the numbers together, and all the variables

-6x^2

Back to the equation:

+(-6x^2)



We get rid of parentheses

-6x^2+6xx=0

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