3/2(16n+3)=1/4(d-2)

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Solution for 3/2(16n+3)=1/4(d-2) equation: 


x in (-oo:+oo)

(3/2)*(16*n+3) = (1/4)*(d-2) // - (1/4)*(d-2)

(3/2)*(16*n+3)-((1/4)*(d-2)) = 0

(3/2)*(16*n+3)+(-1/4)*(d-2) = 0

3/2*(16*n+3)-1/4*(d-2) = 0

3/2*(16*n+3)-1/4*(d-2) = 0

24*n-1/4*d+5 = 0

24*n-1/4*d+5 = 0

x belongs to the empty set

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