3/2(16d+3)=24d

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Solution for 3/2(16d+3)=24d equation: 



3/2(16d+3)=24d

We move all terms to the left:

3/2(16d+3)-(24d)=0



Domain of the equation: 2(16d+3)!=0

d∈R



We add all the numbers together, and all the variables

-24d+3/2(16d+3)=0

We multiply all the terms by the denominator


-24d*2(16d+3)+3=0

Wy multiply elements

-48d^2(1+3=0

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