3/2(1+3x)=2/3(2-3x)

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Solution for 3/2(1+3x)=2/3(2-3x) equation: 



3/2(1+3x)=2/3(2-3x)

We move all terms to the left:

3/2(1+3x)-(2/3(2-3x))=0



Domain of the equation: 2(1+3x)!=0

x∈R





Domain of the equation: 3(2-3x))!=0

x∈R



We add all the numbers together, and all the variables

3/2(3x+1)-(2/3(-3x+2))=0

We calculate fractions


(9x(-)/(2(3x+1)*3(-3x+2)))+(-4x3/(2(3x+1)*3(-3x+2)))=0



We calculate terms in parentheses: +(9x(-)/(2(3x+1)*3(-3x+2))), so:

9x(-)/(2(3x+1)*3(-3x+2))

We add all the numbers together, and all the variables

9x0/(2(3x+1)*3(-3x+2))

We multiply all the terms by the denominator


9x0

We add all the numbers together, and all the variables

9x

Back to the equation:

+(9x)





We calculate terms in parentheses: +(-4x3/(2(3x+1)*3(-3x+2))), so:

-4x3/(2(3x+1)*3(-3x+2))

We multiply all the terms by the denominator


-4x3

We add all the numbers together, and all the variables

-4x^3

We do not support expression: x^3

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