3/2(-2x+4)=-6x+42

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Solution for 3/2(-2x+4)=-6x+42 equation: 



3/2(-2x+4)=-6x+42

We move all terms to the left:

3/2(-2x+4)-(-6x+42)=0



Domain of the equation: 2(-2x+4)!=0

x∈R



We get rid of parentheses

3/2(-2x+4)+6x-42=0

We multiply all the terms by the denominator


6x*2(-2x+4)-42*2(-2x+4)+3=0

Wy multiply elements

12x^2(--84x(-+3=0

We use the square of the difference formula

12x^2(+84x(-3=0

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