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3/10x=3x-18
We move all terms to the left:
3/10x-(3x-18)=0
Domain of the equation: 10x!=0We get rid of parentheses
x!=0/10
x!=0
x∈R
3/10x-3x+18=0
We multiply all the terms by the denominator
-3x*10x+18*10x+3=0
Wy multiply elements
-30x^2+180x+3=0
a = -30; b = 180; c = +3;
Δ = b2-4ac
Δ = 1802-4·(-30)·3
Δ = 32760
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{32760}=\sqrt{36*910}=\sqrt{36}*\sqrt{910}=6\sqrt{910}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(180)-6\sqrt{910}}{2*-30}=\frac{-180-6\sqrt{910}}{-60} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(180)+6\sqrt{910}}{2*-30}=\frac{-180+6\sqrt{910}}{-60} $
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