3/10(y+2)=-6.3

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Solution for 3/10(y+2)=-6.3 equation: 



3/10(y+2)=-6.3

We move all terms to the left:

3/10(y+2)-(-6.3)=0



Domain of the equation: 10(y+2)!=0

y∈R



We add all the numbers together, and all the variables

3/10(y+2)+6.3=0

We multiply all the terms by the denominator


(6.3)*10(y+2)+3=0

We move all terms containing y to the left, all other terms to the right

(6.3)*10(y+2)=-3

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