3/10(m-18)=6/10m

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Solution for 3/10(m-18)=6/10m equation: 



3/10(m-18)=6/10m

We move all terms to the left:

3/10(m-18)-(6/10m)=0



Domain of the equation: 10(m-18)!=0

m∈R





Domain of the equation: 10m)!=0

m!=0/1

m!=0

m∈R



We add all the numbers together, and all the variables

3/10(m-18)-(+6/10m)=0

We get rid of parentheses

3/10(m-18)-6/10m=0

We calculate fractions


30m/(100m^2-1800m)+(-60mm/(100m^2-1800m)=0



We calculate terms in parentheses: +(-60mm/(100m^2-1800m), so:

-60mm/(100m^2-1800m

We multiply all the terms by the denominator


-60mm

Back to the equation:

+(-60mm)



We get rid of parentheses

30m/(100m^2-1800m)-60mm=0

We multiply all the terms by the denominator


30m-60mm*(100m^2-1800m)=0

We multiply parentheses

-6000m^3+108000m^2+30m=0

We do not support empression: m^3

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