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3/10(2x+41)=x
We move all terms to the left:
3/10(2x+41)-(x)=0
Domain of the equation: 10(2x+41)!=0We add all the numbers together, and all the variables
x∈R
-1x+3/10(2x+41)=0
We multiply all the terms by the denominator
-1x*10(2x+41)+3=0
Wy multiply elements
-10x^2(2+3=0
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