3/(x+1)=2/(x-3)

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Solution for 3/(x+1)=2/(x-3) equation: 



3/(x+1)=2/(x-3)

We move all terms to the left:

3/(x+1)-(2/(x-3))=0



Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R





Domain of the equation: (x-3))!=0

x∈R



We calculate fractions


3x/((x+1)*(x-3)))+(-(2*(x+1))/((x+1)*(x-3)))=0



We calculate terms in parentheses: -(2*(x+1))/((x+1)*(x-3))), so:

2*(x+1))/((x+1)*(x-3))

We multiply all the terms by the denominator


2*(x+1))

We multiply parentheses

2x+

We add all the numbers together, and all the variables

2x

Back to the equation:

-(2x)



We add all the numbers together, and all the variables

-2x+3x/((x+1)*(x-3)))+(=0

We multiply all the terms by the denominator


-2x*((x+1)*(x-3)))+(+3x=0

We add all the numbers together, and all the variables

3x-2x*((x+1)*(x-3)))+(=0

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