3/(a+2)=1/(a+4)

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Solution for 3/(a+2)=1/(a+4) equation: 


D( a )

a+2 = 0

a+4 = 0

a+2 = 0

a+2 = 0

a+2 = 0 // - 2

a = -2

a+4 = 0

a+4 = 0

a+4 = 0 // - 4

a = -4

a in (-oo:-4) U (-4:-2) U (-2:+oo)

3/(a+2) = 1/(a+4) // - 1/(a+4)

3/(a+2)-(1/(a+4)) = 0

3/(a+2)-(a+4)^-1 = 0

3/(a+2)-1/(a+4) = 0

(3*(a+4))/((a+2)*(a+4))+(-1*(a+2))/((a+2)*(a+4)) = 0

3*(a+4)-1*(a+2) = 0

2*a+10 = 0

(2*a+10)/((a+2)*(a+4)) = 0

(2*a+10)/((a+2)*(a+4)) = 0 // * (a+2)*(a+4)

2*a+10 = 0

2*a+10 = 0 // - 10

2*a = -10 // : 2

a = -10/2

a = -5

a = -5

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