3/(7x+4)=7/(x-2)

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Solution for 3/(7x+4)=7/(x-2) equation: 


D( x )

x-2 = 0

7*x+4 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

7*x+4 = 0

7*x+4 = 0

7*x+4 = 0 // - 4

7*x = -4 // : 7

x = -4/7

x in (-oo:-4/7) U (-4/7:2) U (2:+oo)

3/(7*x+4) = 7/(x-2) // - 7/(x-2)

3/(7*x+4)-(7/(x-2)) = 0

3/(7*x+4)-7*(x-2)^-1 = 0

3/(7*x+4)-7/(x-2) = 0

(3*(x-2))/((7*x+4)*(x-2))+(-7*(7*x+4))/((7*x+4)*(x-2)) = 0

3*(x-2)-7*(7*x+4) = 0

-46*x-34 = 0

(-46*x-34)/((7*x+4)*(x-2)) = 0

(-46*x-34)/((7*x+4)*(x-2)) = 0 // * (7*x+4)*(x-2)

-46*x-34 = 0

-46*x-34 = 0 // + 34

-46*x = 34 // : -46

x = 34/(-46)

x = -17/23

x = -17/23

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