3/(3y)=y/(2y)

Solution for 3/(3y)=y/(2y) equation:

3/(3y)=y/(2y)

We move all terms to the left:

3/(3y)-(y/(2y))=0


Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R



Domain of the equation: 2y)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

3/3y-(+y/2y)=0

We get rid of parentheses

3/3y-y/2y=0

We calculate fractions


(-3y^2)/6y^2+6y/6y^2=0

We multiply all the terms by the denominator


(-3y^2)+6y=0

We get rid of parentheses

-3y^2+6y=0

a = -3; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-3)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-3}=\frac{-12}{-6}
=+2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-3}=\frac{0}{-6}
=0
$