3/(2z+1)-1/(z+2)

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Solution for 3/(2z+1)-1/(z+2) equation: 


D( z )

z+2 = 0

2*z+1 = 0

z+2 = 0

z+2 = 0

z+2 = 0 // - 2

z = -2

2*z+1 = 0

2*z+1 = 0

2*z+1 = 0 // - 1

2*z = -1 // : 2

z = -1/2

z in (-oo:-2) U (-2:-1/2) U (-1/2:+oo)

3/(2*z+1)-(1/(z+2)) = 0

3/(2*z+1)-(z+2)^-1 = 0

3/(2*z+1)-1/(z+2) = 0

(3*(z+2))/((2*z+1)*(z+2))+(-1*(2*z+1))/((2*z+1)*(z+2)) = 0

3*(z+2)-1*(2*z+1) = 0

z+5 = 0

(z+5)/((2*z+1)*(z+2)) = 0

(z+5)/((2*z+1)*(z+2)) = 0 // * (2*z+1)*(z+2)

z+5 = 0

z+5 = 0 // - 5

z = -5

z = -5

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