3/(2x)-7/5=4(5x)-5/2

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Solution for 3/(2x)-7/5=4(5x)-5/2 equation:


D( x )

2*x = 0

2*x = 0

2*x = 0

2*x = 0 // : 2

x = 0

x in (-oo:0) U (0:+oo)

3/(2*x)-(7/5) = 4*5*x-(5/2) // - 4*5*x-(5/2)

3/(2*x)-(4*5*x)-(7/5)+5/2 = 0

3/(2*x)-20*x-7/5+5/2 = 0

3/2*x^-1-20*x^1+11/10*x^0 = 0

(11/10*x^1-20*x^2+3/2*x^0)/(x^1) = 0 // * x^2

x^1*(11/10*x^1-20*x^2+3/2*x^0) = 0

x^1

(11/10)*x-20*x^2+3/2 = 0

(11/10)*x-20*x^2+3/2 = 0

DELTA = (11/10)^2-(-20*4*(3/2))

DELTA = 12121/100

DELTA > 0

x = ((12121/100)^(1/2)-(11/10))/(-20*2) or x = (-(11/10)-(12121/100)^(1/2))/(-20*2)

x = ((12121/100)^(1/2)-11/10)/(-40) or x = ((12121/100)^(1/2)+11/10)/40

x in { ((12121/100)^(1/2)-11/10)/(-40), ((12121/100)^(1/2)+11/10)/40}

x in { ((12121/100)^(1/2)-11/10)/(-40), ((12121/100)^(1/2)+11/10)/40 }

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