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3.5-2g=1/2g-4
We move all terms to the left:
3.5-2g-(1/2g-4)=0
Domain of the equation: 2g-4)!=0We get rid of parentheses
g∈R
-2g-1/2g+4+3.5=0
We multiply all the terms by the denominator
-2g*2g+4*2g+(3.5)*2g-1=0
We multiply parentheses
-2g*2g+4*2g+7g-1=0
Wy multiply elements
-4g^2+8g+7g-1=0
We add all the numbers together, and all the variables
-4g^2+15g-1=0
a = -4; b = 15; c = -1;
Δ = b2-4ac
Δ = 152-4·(-4)·(-1)
Δ = 209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{209}}{2*-4}=\frac{-15-\sqrt{209}}{-8} $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{209}}{2*-4}=\frac{-15+\sqrt{209}}{-8} $
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