3-x=(48-4x)/7

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Solution for 3-x=(48-4x)/7 equation:



3-x=(48-4x)/7
We move all terms to the left:
3-x-((48-4x)/7)=0
We add all the numbers together, and all the variables
-x-((-4x+48)/7)+3=0
We add all the numbers together, and all the variables
-1x-((-4x+48)/7)+3=0
We multiply all the terms by the denominator
-1x*7)-((-4x+48)+3*7)=0
We add all the numbers together, and all the variables
-1x*7)-((-4x+48)=0
Wy multiply elements
-7x^2=0
a = -7; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-7)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-14}=0$

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