3-x+1=18x-2(x-1)

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Solution for 3-x+1=18x-2(x-1) equation: 



3-x+1=18x-2(x-1)

We move all terms to the left:

3-x+1-(18x-2(x-1))=0

We add all the numbers together, and all the variables

-1x-(18x-2(x-1))+4=0



We calculate terms in parentheses: -(18x-2(x-1)), so:

18x-2(x-1)

We multiply parentheses

18x-2x+2

We add all the numbers together, and all the variables

16x+2

Back to the equation:

-(16x+2)



We get rid of parentheses

-1x-16x-2+4=0

We add all the numbers together, and all the variables

-17x+2=0

We move all terms containing x to the left, all other terms to the right

-17x=-2

x=-2/-17

x=2/17

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