3-x+(4/x+4)

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Solution for 3-x+(4/x+4) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4/x-x+3+4 = 0

4*x^-1-1*x^1+7*x^0 = 0

(7*x^1-1*x^2+4*x^0)/(x^1) = 0 // * x^2

x^1*(7*x^1-1*x^2+4*x^0) = 0

x^1

7*x-x^2+4 = 0

7*x-x^2+4 = 0

DELTA = 7^2-(-1*4*4)

DELTA = 65

DELTA > 0

x = (65^(1/2)-7)/(-1*2) or x = (-65^(1/2)-7)/(-1*2)

x = (65^(1/2)-7)/(-2) or x = (65^(1/2)+7)/2

x in { (65^(1/2)-7)/(-2), (65^(1/2)+7)/2} 

x in { (65^(1/2)-7)/(-2), (65^(1/2)+7)/2 }

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