3-7(1-6x)=2+4x

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Solution for 3-7(1-6x)=2+4x equation: 



3-7(1-6x)=2+4x

We move all terms to the left:

3-7(1-6x)-(2+4x)=0

We add all the numbers together, and all the variables

-7(-6x+1)-(4x+2)+3=0

We multiply parentheses

42x-(4x+2)-7+3=0

We get rid of parentheses

42x-4x-2-7+3=0

We add all the numbers together, and all the variables

38x-6=0

We move all terms containing x to the left, all other terms to the right

38x=6

x=6/38

x=3/19

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