3-5i/2i

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Solution for 3-5i/2i equation: 


i in (-oo:+oo)

3-(((5*i)/2)*i) = 0

(-5/2)*i^2+3 = 0

-5/2*i^2 = -3 // : -5/2

i^2 = 6/5

i^2 = 6/5 // ^ 1/2

abs(i) = (6/5)^(1/2)

i = (6/5)^(1/2) or i = -(6/5)^(1/2)

i in { (6/5)^(1/2), -(6/5)^(1/2) }

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